Find the sum of the sequence ^@5, 55, 555, 5555, ... ^@ to ^@ n | Math Question and Answer

Answer:

$\dfrac{ 5 } { 9 } \left[ \dfrac{ 10(10^n-1) }{9} -n \right]$

Step by Step Explanation:

The given sequence is not a $G.P.,$ however, we can relate it to a $G.P.$ by writing the given sequence differently.
The sum of the given sequence up to $n$ terms can be written as
$\begin{align} S_n &= 5 + 55 + 555 + 5555 + \space .... \text{ to n terms}. \\ &= 5 [1 + 11 + 111 + 1111 + \space .... \text{ to n terms}] \\ &= \dfrac{ 5 } { 9 }[9 + 99 + 999 + 9999 + \space .... \text{ to n terms}] \\ &= \dfrac{ 5 } { 9 }[(10-1) + (10^2-1) + (10^3-1) + (10^4-1) + \space .... \text{ to n terms}] \\ &= \dfrac{ 5 } { 9 } \left[(10 + 10^2 + 10^3 + 10^4 + \space .... \text{ to n terms}) - (1+1+1+1 \space .... \text{ to n terms}) \right] \\ &= \dfrac{ 5 } { 9 } \left[ \dfrac{ 10(10^n-1) }{10-1} -n \right] \\ &= \dfrac{ 5 } { 9 } \left[ \dfrac{ 10(10^n-1) }{9} -n \right] \end{align}$
Hence, the sum of the sequence $5, 55, 555, 5555, ...$ to $n$ terms is $\dfrac{ 5 } { 9 } \left[ \dfrac{ 10(10^n-1) }{9} -n \right]$ .

You can reuse this answer
Creative Commons License