Assume you roll a die 2 times. What is the probability that you will get exactly one 6?
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Answer:
Step by Step Explanation: - According to the question, a die rolled 2 times
So, the Sample Space(S) is { (i, j): i, j = 1, 2, 3, 4, 5, 6 } - Total number of outcomes in sample space n(S) = 6 × 6 = 36
- Let E be the event that you will get exactly one 6.
Number of outcomes in which '6' appears only on the first throw = 1 × 5 = 5
As the die is thrown 2 times, '6' (appearing exactly once) can appear on any of the 2 throws.
Therefore, the total number of outcomes when 6 appears exactly once, n(E) = 2 × 5 = 10 - Probability, P(E) = =
- Therefore, the probability of getting exactly one
6
is .